MCQ
The factorisation of $3 x^{2}+10 x+8$ is
- ✓$(3 x+4)(x+2)$
- B$(3 x-4)(x-2)$
- C$(3 x+4)(x-2)$
- D$(3 x-4)(x+2)$
✓
Answer
Correct option: A.
$(3 x+4)(x+2)$
a
$3 x^{2}+10 x+8=3 x^{2}+6 x+4 x+8$
$=3 x(x+2)+4(x+2)$
$=(x+2)(3 x+4)$
$3 x^{2}+10 x+8=3 x^{2}+6 x+4 x+8$
$=3 x(x+2)+4(x+2)$
$=(x+2)(3 x+4)$
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