MCQ
The factorisation of $6-x-2 x^{2}$ is
- ✓$(2+x)(3-2 x)$
- B$(2+x)(3+2 x)$
- C$(2-x)(3-2 x)$
- D$(2-x)(3+2 x)$
✓
Answer
Correct option: A.
$(2+x)(3-2 x)$
a
$6-x-2 x^{2}$
$=6+3 x-4 x-2 x^{2}$
$=3(2+x)-2 x(2+x)$
$=(2+x)(3-2 x)$
$6-x-2 x^{2}$
$=6+3 x-4 x-2 x^{2}$
$=3(2+x)-2 x(2+x)$
$=(2+x)(3-2 x)$
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