- A$8.29\, eV, 9.32\, eV$
- B$9.32\, eV, 9.32\, eV$
- C$8.29\, eV, 8.29\, eV$
- ✓$9.32\, eV, 8.29\, eV$
According to theory as we move from lest to right in a period the ionization potential should increase but in case of $B e$ and $B$ Beryllium is having more ionization potential than Boran due to completely filled s orbital in Beryllium $\left(1 s^{2} 2 s^{2}\right)$.
Hence option D is correct.
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$(B)$ $I _{2}+ H _{2} O _{2}+2 OH ^{-} \rightarrow 2 I ^{-}+2 H _{2} O + O _{2}$
Choose the correct option.
Statement $I$ : The metallic radius of $\mathrm{Na}$ is $1.86 \mathrm{~A}^{\circ}$ and the ionic radius of $\mathrm{Na}^{+}$is lesser than $1.86 \mathrm{~A}^{\circ}$.
Statement $II$ : Ions are always smaller in size than the corresponding elements.
In the light of the above statements, choose the correct answer from the options given below :
