Question
The first term a and common difference d are given. Find first four terms of A.P :
$a=-1, d=-\frac{1}{2}$
✓
Answer
$\begin{array}{l} a=-1, d=-\frac{1}{2} \
a=t_1=-1 \
t_2=t_1+d=-1+\left(-\frac{1}{2}\right)=-\frac{3}{2} \
t_3=t_2+d=-\frac{3}{2}+\left(-\frac{1}{2}\right)=-\frac{4}{2}=-2 \
t_4=t_3+d=-2+\left(-\frac{1}{2}\right) \
=-2-\frac{1}{2}=-\frac{5}{2} \
\text { P. is }=-1,-\frac{3}{2},-2,-\frac{5}{2}, \ldots
\end{array}
$
$\therefore$ A.P. is $=-1,-\frac{3}{2},-2,-\frac{5}{2}, \ldots$.
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