- AChromium
- ✓Scandium
- CNickel
- DCopper
Correct option is B. scandium
The $d-b l o c k$ elements that are the elements from a group $3-12$ are called transition elements. This is because their physical and chemical properties are intermediate between $s-b l o c k$ and $p-$ block properties. Hence these elements act as a bridge from $s-b l o c k$ to $p-b l o c k$ and hence they are known as transition. They have several oxidation states. They usually form colored compounds. An atomic number of these metals is from $21-30,39-48,57,72-80,89$, and $104-112$.
$\because$ The First main series of Transition elements starts with Scandium(Atomic no $=21)$ end with $\operatorname{Zinc}($ Atomic no $=30)$
$\therefore$ The first element of transition element is Scandium
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(Given : Molar Mass $\mathrm{Na}: 23$ and $\mathrm{Cl}: 35.5 \mathrm{gmol}^{-1}$ )
$\left\{ en = H _2 NCH _2 CH _2 NH _2\right.$; atomic numbers: $\left.Ti =22 ; Cr =24 ; Cp =27 ; Pt =78\right\}$
| List-$I$ | List-$II$ |
| $P.$ $\left[ Cr \left( NH _3\right)_4 Cl _2\right) Cl ]$ | $1.$ Paramagnetic and exhibits ionisation isomerism |
| $Q.$ $\left[ Ti \left( H _2 O \right)_5 Cl \right]\left( NO _3\right)_2$ | $2.$ Diamagentic and exhibits cis-trans isomerism |
| $R.$ $\left[ Pt ( en )\left( NH _3\right) Cl \right] NO _3$ | $3.$ Paramagentic and exhibits cis-trans isomerism |
| $S.$ $\left[ Co \left( NH _3\right)_4\left( NO _3\right)_2\right] NO _3$ | $4.$ Diamagentic and exhibits ionisation isomerism |
Codes: $ \quad P \quad Q \quad R \quad S $