Question
The Fischer projection formula of is
✓
Answer
c
In Fischer Projection formula, the longest chain of carbon atom is shown by vertical line and branches and groups attached to the chain by a horizontal line.
In Fischer Projection formula, the longest chain of carbon atom is shown by vertical line and branches and groups attached to the chain by a horizontal line.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
$100\ gm$ each solution, one containing $20\%$ by mass of $NaOH$ and other $40\%$ by mass of $NaOH$ are mixed and the density of the resulting solution is $1.25\ gm/ ml$ . Find the new $\%$ $w/v$ of $NaOH$ in the final solution ....... $\%$.
→Which of the following is an organo silicon polymer?
The compound shown in the below undergoes racemization on reaction with aqueous acid
Which of the following structures best represents the intermediate responsible for this process?
Most stable conformation of butane $-1,4-$ dioic acid is
→Which of the following is not permissible arrangement of electrons in an atom
Only $2 \mathrm{~mL}$ of $\mathrm{KMnO}_4$ solution of unknown molarity is required to reach the end point of a titration of $20 \mathrm{~mL}$ of oxalic acid ($2$ M) in acidic medium. The molarity of $\mathrm{KMnO}_4$ solution should be . . . . . . . . . $M$.
→${H_2}{O_{\left( g \right)}} + {C_{\left( s \right)}} \to C{O_{\left( g \right)}} + {H_2}\left( g \right)\,;\,\Delta H = 100\,kJ$
→$C{O_{\left( g \right)}} + \frac{1}{2}{O_{2\left( g \right)}} \to C{O_{2\left( g \right)}}\,;\,\Delta H = - 300\,kJ$
${H_2}_{\left( g \right)} + \frac{1}{2}{O_2}_{\left( g \right)} \to {H_2}{O_{\left( g \right)}}\,;\,\Delta H = - 250\,kJ$
$C_{(s)} + O_{2(g)} \to CO_{2(g)} ; \Delta H = -x\, kJ$
The value of $x$ will be
Out of the following the best category of proteins is
Which behaves both as a nucleophile and electrophile
Calculate the number of atoms of oxygen present in $176\, g$ of $CO_2$
→