Question
The following figure have been split into rectangles. Find the area. (The measures are given in centimeter)
✓
Answer
This figure consists of two rectangles $II$ and $IV$ and two squares $I$ and $III$. Area of square $I =$ (Side $\times $ Side)
$= (3 \times 3)$
$= 9\ cm^2$
Similarity, area of rectangle $II =$ (Side $\times $ Side)
$= (2 \times 1)$
$ = 2\ cm^2$
Area of square $III =$ (Side $\times $ Side)
$= (3 \times 3)$
$ = 9\ cm^2$
Area of rectangle $IV =$ (Side $\times $ Side)
$= (2 \times 4)$
$= 8\ cm^2$
Thus, the total area of this figure $=$ (Area of square $I +$ Area of rectangle $II +$ Area of square $III +$ Area of rectangle $IV)$
$= (9 + 2 + 9 + 8)$
$ = 28\ cm^2$
$= (3 \times 3)$
$= 9\ cm^2$
Similarity, area of rectangle $II =$ (Side $\times $ Side)
$= (2 \times 1)$
$ = 2\ cm^2$
Area of square $III =$ (Side $\times $ Side)
$= (3 \times 3)$
$ = 9\ cm^2$
Area of rectangle $IV =$ (Side $\times $ Side)
$= (2 \times 4)$
$= 8\ cm^2$
Thus, the total area of this figure $=$ (Area of square $I +$ Area of rectangle $II +$ Area of square $III +$ Area of rectangle $IV)$
$= (9 + 2 + 9 + 8)$
$ = 28\ cm^2$
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