Question
The following figure shows a parallelogram ABCD whose side AB is parallel to the x-axis. ∠A = 60° and vertex C = (7, 5). Find the equations of BC and CD.
Image

Answer

Since, ABCD is a parallelogram,
$\angle A + \angle B = 180^\circ$
$\angle B = 180^\circ - 60^\circ = 120^\circ$
Slope of $BC =\tan 120^\circ = \tan (90^\circ + 30^\circ) = \cot 30^\circ =\sqrt{3}$
Equation of the line BC is given by:
$y − y_1 = m (x − x_1)$
$y-5=\sqrt{3}(x-7)$
$y-5=\sqrt{3} x-7 \sqrt{3}$
$y=\sqrt{3} x+5-7 \sqrt{3}$
Since, CD || AB and AB || x-axis, slope of CD = Slope of AB = 0
Equation of the line CD is given by:
$y − y_1 = m (x - x_1)$
$y − 5 = 0(x − 7)$
$y = 5$

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