MCQ
The forces acting between noble gas atoms are
- ✓Vander Waals forces
- BIon-dipole forces
- CLondon dispersion forces
- DMagnetic forces
✓
Answer
Correct option: A.
Vander Waals forces
a
The forces acting between noble gas atoms are van der Waal's forces.
The forces acting between noble gas atoms are van der Waal's forces.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The first and second ionisation enthalpies of a metal are $496$ and $4560 \;\mathrm{kJ} \mathrm{mol}^{-1},$ respectively. How many moles of $\mathrm{HCl}$ and $\mathrm{H}_{2} \mathrm{SO}_{4}$ respectively, will be needed to react completely with $1$ mole of the metal hydroxide?
→If $ ‘I’$ is the intensity of absorbed light and $C$ is the concentration of $AB$ for the photochemical process $AB + hv \to AB^*,$ the rate of formation of $AB^*$ is directly proportional to
→Cylohexene $image$ is __________type of an organic compound.
→Calculate the weight of non-volatile solute having molecular weight $40,$ which is dissolved in $57\,g$ octane to reduce its vapour pressure by $20\%$ .......... $g$.
→Tin is obtained from cassiterite by reduction with coke. Use the data given below to determine the minimum temperature (in $K$ ) at which the reduction of cassiterite by coke would take place.
→At $ 298 K : \Delta_{ f } H ^{\circ}\left( SnO _2( s )\right)=-581.0 kJ mol ^{-1}, \Delta_{ fH } H ^{\circ}\left( CO _2( g )\right)=-394.0 kJ mol ^{-1}$
$S ^{\circ}\left( SnO _2( s )\right)=56.0 J K ^{-1} mol ^{-1}, S ^{\circ}( Sn ( s ))=52.0 J K ^{-1} mol ^{-1}$
$S ^{\circ}( C ( s ))=6.0 J K ^{-1} mol ^{-1}, S ^{\circ}\left( CO _2( g )\right)=210.0 J K ^{-1} mol ^{-1}$
Assume that the enthalpies and the entropies are temperature independent.
The total number of orbitals associated with the principal quantum number $5$ is
→General configuration of outermost and penultimate shell is $(n - 1)\,{s^2}\,(n - 1)\,\,{p^6}(n - 1)\,\,{d^x}n{s^2}.$ If $n = 4$ and $ x = 5$ then no. of proton in the nucleus will be
→The value of $\Delta H$ for the reaction $X_{2(g)} + 4Y_{2(g)} \rightleftharpoons XY_{4(g)}$ is less than zero. Formation of $XY_{4(g)}$ will be favoured at
→For $s-$ orbitals, since $\psi $ (orbital) is independent of angles, the probability $( \psi ^2)$ is
→Assertion : Resorcinol turns $FeCl_3$ solution purple.
Reason : Resorcinol have phenolic group
→Reason : Resorcinol have phenolic group