MCQ
The formation of diethyl ether from ethanol is based on
- ADehydrogenation reaction
- BHydrogenation reaction
- CDehydration reaction
- ✓Heterolytic fission reaction
✓
Answer
Correct option: D.
Heterolytic fission reaction
d
Writing the structure, we get
Writing the structure, we get
$(a)$ $\begin{array}{*{20}{c}}
{\,\,\,\,\,\begin{array}{*{20}{c}}
{\,I} \\
|
\end{array}} \\
{C{H_3} - C - H} \\
{\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$ , Isopropyl iodide $(2^o)$
$(b)$ $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,H\,\,\,\,\,\,H\,\,\,\,\,H} \\
{\,\,\,|\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,|}
\end{array}} \\
{H - C - C - C - I} \\
{\,\,\,\,|\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,|\,} \\
{\,\,\,\,\,\,\,\,\,\,H\,\,\,\,\,\,H\,\,\,\,\,C{H_3}}
\end{array}$, sec- Butyl iodide $(2^o)$
$(c)$ $\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\begin{array}{*{20}{c}}
{\,\,\,\,\,\,C{H_3}} \\
|
\end{array}\,} \\
{{H_3}C - C - I} \\
{\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$ , tert - Butyl iodide $(3^o)$
$(d)$ $\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\begin{array}{*{20}{c}}
{\,\,\,C{H_3}\,\,H\,\,} \\
{|\,\,\,\,\,\,\,\,\,|}
\end{array}} \\
{C{H_3} - C{H_2} - C - C - Cl} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,|\,} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,CH{\,_3}\,H\,\,\,\,\,\,}
\end{array}$, Neohexyl chloride $(1^o)$
Thus, $(d)$ is a primary $(1^o)$ halide.
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