MCQ
The formula of alum is
- ✓${K_2}S{O_4}.A{l_2}{(S{O_4})_3}.24{H_2}O$
- B${K_4}[Fe{(CN)_6}]$
- C${K_2}S{O_4}.A{l_2}{(S{O_4})_3}.6{H_2}O$
- D$N{a_2}C{O_3}.10{H_2}O$
✓
Answer
Correct option: A.
${K_2}S{O_4}.A{l_2}{(S{O_4})_3}.24{H_2}O$
a
(a)General formula for alum is
(a)General formula for alum is
${M_2}S{O_4}.{R_2}{(S{O_4})_3}.24{H_2}O$
$M = $ mono valent cation $({K^ + },\,N{a^ + }....)$
$R = $Trivalent cation $(A{l^{ + 3}},\,F{e^{ + 3}})$
Hence, ${K_2}S{O_4}A{l_2}{(S{O_4})_2}.24{H_2}O$ represent an alum.
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