MCQ
The formula of the complex hydridotrimethoxyborate $(III)$ ion is :
- ✓$[BH(OCH_3)_3]^{2-}$
- B$[BH_2(OCH_3)_3]^{2-}$
- C$[BH(OCH_3)_3]^-$
- D$[BH(OCH_3)_3]^+$
✓
Answer
Correct option: A.
$[BH(OCH_3)_3]^{2-}$
a
$\mathrm{Mn}^{2+}=\mathrm{d}^{5}=\mathrm{t}_{2 \mathrm{g}}^{3} \mathrm{e}_{\mathrm{g}}^{2} \Rightarrow \mathrm{CFSE}=0$
$\mathrm{Mn}^{2+}=\mathrm{d}^{5}=\mathrm{t}_{2 \mathrm{g}}^{3} \mathrm{e}_{\mathrm{g}}^{2} \Rightarrow \mathrm{CFSE}=0$
$\mathrm{Co}^{+3}=\mathrm{d}^{6}=\mathrm{t}_{2 \mathrm{g}}^{6}$
$\mathrm{Fe}^{3+}=\mathrm{d}^{5}=\mathrm{t}_{2 \mathrm{g}}^{5}$
$\mathrm{Ni}^{2+}=\mathrm{d}^{8}=\mathrm{t}_{2 \mathrm{g}}^{6} \mathrm{e}_{g}^{2}$
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Then incorrect option is
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{Ph - C{H_2} - CH - C{H_3}\,\xrightarrow[{hv}]{{C{l_2}(1\,\,mol)}}}
\end{array}$ Major product
→{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{Ph - C{H_2} - CH - C{H_3}\,\xrightarrow[{hv}]{{C{l_2}(1\,\,mol)}}}
\end{array}$ Major product
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→