MCQ
The formula of the complex hydridotrimethoxyborate $(III)$ ion is :
- ✓$[BH(OCH_3)_3]^{2-}$
- B$[BH_2(OCH_3)_3]^{2-}$
- C$[BH(OCH_3)_3]^-$
- D$[BH(OCH_3)_3]^+$
✓
Answer
Correct option: A.
$[BH(OCH_3)_3]^{2-}$
a
$\mathrm{Mn}^{2+}=\mathrm{d}^{5}=\mathrm{t}_{2 \mathrm{g}}^{3} \mathrm{e}_{\mathrm{g}}^{2} \Rightarrow \mathrm{CFSE}=0$
$\mathrm{Mn}^{2+}=\mathrm{d}^{5}=\mathrm{t}_{2 \mathrm{g}}^{3} \mathrm{e}_{\mathrm{g}}^{2} \Rightarrow \mathrm{CFSE}=0$
$\mathrm{Co}^{+3}=\mathrm{d}^{6}=\mathrm{t}_{2 \mathrm{g}}^{6}$
$\mathrm{Fe}^{3+}=\mathrm{d}^{5}=\mathrm{t}_{2 \mathrm{g}}^{5}$
$\mathrm{Ni}^{2+}=\mathrm{d}^{8}=\mathrm{t}_{2 \mathrm{g}}^{6} \mathrm{e}_{g}^{2}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The $IUPAC$ name of given is :
→The oxidation number of $N$ in $N{H_4}Cl$ is
→The major product expected, when Phthalamide is treated with $NaOH,$ is
→Maximum number of $P-H$ bond $(s)$ are there in a molecule of
→$\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,C{H_3}\,\,} \\
|\,\,\,
\end{array}\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - O - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,C{H_3}\,\,\,\,}
\end{array}$ $\xrightarrow[{(cold)}]{{HI}}$ Product is
→{\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,C{H_3}\,\,} \\
|\,\,\,
\end{array}\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - O - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,C{H_3}\,\,\,\,}
\end{array}$ $\xrightarrow[{(cold)}]{{HI}}$ Product is
Match list $I$ with list $II$ and then select the correct answer from the codes given below the lists
→| list $I$ | list $II$ |
| $(A)$ Butane $\to$ Isobutane | $(a)$ Cracking |
| $(B)$ Butane $\to$ Lower hydrocarbons | $(b)$ Isomerisation |
| $(C)$ $n-$ Heptane $\to $ Toluene | $(c)$ Reed reaction |
| $(D)$ Propane $\to$ $CH_3CH_2CH_2SO_2Cl$ | $(d)$ Aromatizatio |
A solution of $FeC{l_3}$ in water acts as acidic due to
→The approximate $pH$ of a solution formed by mixing equal volumes of solution of $0.1\,M$ sodium propanoate and $0.1\,M$ propanoic acid (if the dissociation constant of propanoic acid is $1.3\times10^{-5}$) will be
→Complete the following reaction : $R\,\,N{H_2} + {H_2}S{O_4} \to $
→Find incorrect comparison of second ionisation energy