Question
The formula unit mass of $\ce{Ca3(PO4​)2}$​ is :

Answer

Mass of $\ce{Ca3(PO4)2}​$
$= (3 \ \times$ atomic mass of $Ca) \ +\  (2\  \times$ atomic mass of phosphorus$) \ +\  (8 \ \times$ atomic mass of oxygen$)$
$=3 \times 40 + 2 \times 31 + 8 \times 16 = 310$

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