MCQ
The freezing point of equimolal aqueous solution will be highest for
- A$C_6H_5NH_3^+Cl^-$
- B$Ca(NO_3)_2$
- C$La(NO_3)_2$
- ✓$C_6H_{12}O_6$
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|
List $-I$ (Ion involved) |
List $-II$ (agent) |
| $(i)\, Ni^{2+}$ | $(A)$ Sodium thiosulphate |
| $(ii)\, Ag^+$ | $(B)$ Sodium nitroprusside |
| $(iii)\, Cu^{2+}$ | $(C)$ Ammonia |
| $(iv)\,S^{2-}$ | $(D)$ Dimethylglyoxime |
$(i)\,\,\,-\,\,\,(ii)\,\,\,-\,\,\,(iii)\,\,\,-\,\,\,(iv)$
Reason : Chlorination of $CH_4$ takes place in sunlight.

because
$STATEMENT$-$2$: The small size of $\mathrm{B}^{3+}$ favours formation of covalent bond.
$\left[\right.$ Given : $pK _{ b }\left( NH _3\right)=4.745$
$\log 2=0.301$
$\log 3=0.477$
$T =298\,K ]$