- The saturation photocurrent remains almost the same.
- The maximum kinetic energy of the photoelectrons is doubled.
- Both A and Bare true.
- A is true but B is false.
- A is false but B is true.
- Both A and B are false.
Explanation:
Saturated current varies directly with the intensity of light. As the intensity of light is increased, a large number of photons fall on the metal surface. As a result, a large number of electrons interact with the photons. As a result, the number of emitted electrons increases and, hence, the current also increases.
At the same time, the frequency of the light source also increases.Also, with the increase in frequency of light, the stopping potential increases as well. This will reduce the current. The combined effect of these two is that the current will remain the same. Hence, A is true.
From the Einstein's photoelectric equation.
$\text{K}_\text{max}= \text{hv}-\varphi$
Where Kmax = kinetic energy of electron
v = frequency of light
$\varphi$ = work function of metal
It is clear from the above equation. As the frequency of light source is doubled, kinetic energy of electron increases. But, it becomes more than the double.
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A block is projected from the Point $A$ of inclined plane $A B$ along its surface with a velocity just sufficient to carry it to the top Point $B$ at a height $10 m$. After reaching the Point $B$ the block slides down on inclined plane $BC$. Time it takes to reach to the point $C$ from point $A$ is $t (\sqrt{2}+1) s$. The value of $t$ is........(use $g =10 m / s ^{2}$ )