MCQ
The function $f$ defined by $f(x) = (x + 2){e^{ - x}}$ is
  • A
    Decreasing for all $x$
  • B
    Decreasing in $( - \infty ,\, - 1)$ and increasing in $( - 1,\infty )$
  • C
    Increasing for all $x$
  • Decreasing in $( - 1,\,\infty )$ and increasing in $( - \infty ,\, - 1)$

Answer

Correct option: D.
Decreasing in $( - 1,\,\infty )$ and increasing in $( - \infty ,\, - 1)$
d
(d) $f(x) = (x + 2){e^{ - x}}$

$f'(x) = {e^{ - x}} - {e^{ - x}}(x + 2)$

$f'(x) = - {e^{ - x}}[x + 1]$

For increasing, $ - {e^{ - x}}(x + 1) > 0$ or ${e^{ - x}}(x + 1) < 0$

${e^{ - x}} > 0$ $(x + 1) < 0$

$x \in ( - \infty ,\,\infty )$ and $x \in ( - \infty , - 1)$

$\therefore x \in ( - \infty , - 1)$

Hence, the function is increasing in $( - \infty ,\, - 1)$

For decreasing, $ - {e^{ - x}}(x + 1) < 0$ or ${e^{ - x}}(x + 1) > 0$, $x \in ( - 1,\,\infty )$

Hence the function is decreasing in $( - 1,\;\infty )$.

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