$f(x)=\frac{4 x^{3}-3 x^{2}}{6}-2 \sin x+(2 x-1) \cos x$
$f^{\prime}(x)=\left(2 x^{2}-x\right)-2 \cos x+2 \cos x-\sin x(2 x-1)$
$\quad=(2 x-1)(x-\sin x)$
for $x>0, x-\sin x>0$
$\quad x<0, x-\sin x<0$
for $x \in(-\infty, 0] \cup\left[\frac{1}{2}, \infty\right), f^{\prime}(x) \geq 0$
for $x \in\left[0, \frac{1}{2}\right], f^{\prime}(x) \leq 0$
$\Rightarrow \quad f(x)$ increases in $\left[\frac{1}{2}, \infty\right)$
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A five-digit number is written down at raddom. The probability that the number is divisible by 5, and no two consecutive digits are identical, is:
$\frac{1}{5}$
$\frac{1}{5}\big(\frac{9}{10}\big)^3$
$\big(\frac{3}{5}\big)^4$
$\text{None of these}$