MCQ
The function $f(x)\, = \left\{ \begin{array}{l}x + 2\,\,\,\,,\,\,\,1 \le x \le 2\\4\,\,\,\,\,\,\,\,\,\,\,,\,\,\,x = 2\\3x - 2\,\,,\,\,\,x > 2\end{array} \right.$ is continuous at
- A$x = 2$ only
- B$x \le 2$
- ✓$x \ge 2$
- DNone of these
hence option $(b)$ cannot even apply.
For $x > 2,\,y = 3x - 2$ which is a straight line, hence continuous.
Further $y = 4$ at $x = 2$.
Hence, the function is continuous at $x = 2$ also (but not at $x = 2$ only).
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.