- Continuous everywhere.
- Continuous at integer points only.
- Continuous at non-integer points only.
- Differentiable everywhere.
Solution:
f(x) = x - x
Consider n be an integer.
$\text{f(x)}=\text{x}-[\text{x}]=\begin{cases}\text{x}-(\text{n}-1)&\text{n}-1\leq\text{x}<\text{n}\\0&\text{x}=\text{n}\\\text{x}-\text{n}&\text{n}\leq\text{x}<\text{n}+1\end{cases}$
Now,
LHL at x = n
$=\lim\limits_{\text{x}\rightarrow\text{n}^{-}}\text{f(x)}=\text{x}-\text{n}-1=\text{x}-\text{n}+1$
RHL at x = n
$=\lim\limits_{\text{x}\rightarrow\text{n}^{+}}\text{f(x)}=\text{x}-\text{n}=\text{x}-\text{nAs},$
$\text{LHL}\neq\text{RHL}$ at x = n
i.e., given function is not continuous at n.
Now, n is any integer. Therefore, given function is not continuous at integers.
Therefore, given points are continuous at non-integer points only.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
The order and degree of the differential equation $\Big(\frac{\text{d}^3\text{y}}{\text{d}\text{x}^3}\Big)^2-3\frac{\text{d}^2\text{y}}{\text{d}\text{x}^2}+2\Big(\frac{\text{d}\text{y}}{\text{d}\text{x}}\Big)^4=\text{y}^4$ are:
If $A^{-1}=\alpha A+\beta I$, where $I$ is an identity matrix of order $2 \times 2$, then $\alpha+\beta$ equals....................
Statement $-I$ : Let $\overrightarrow{\mathrm{a}}=\hat{\mathrm{i}}+2 \hat{\mathrm{j}}-3 \hat{\mathrm{k}}$ and $\vec{b}=2 \hat{i}+\hat{j}-\hat{k}$. Then the vector $\vec{r}$ satisfying $\overrightarrow{\mathrm{a}} \times \overrightarrow{\mathrm{r}}=\overrightarrow{\mathrm{a}} \times \overrightarrow{\mathrm{b}}$ and $\overrightarrow{\mathrm{a}} \cdot \overrightarrow{\mathrm{r}}=0$ is of magnitude $\sqrt{10}$.
Statement $-II$ : In a triangle $A B C, \cos 2 A+\cos 2 B$ $+\cos 2 \mathrm{C} \geq-\frac{3}{2}$