Download App

CONTINUITY AND DIFFERENTIABILITY — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMathsCONTINUITY AND DIFFERENTIABILITY1 Mark
MCQ
The function $\text{f(x)}=\sin^{-1}(\cos\text{x})$ is:
  • A
    Discontinuous at x = 0
  • ✓
    Continuous at x = 0
  • C
    Differentiable at x = 0
  • D
    None of these.
✓

Answer

Correct option: B.
Continuous at x = 0
$\text{f(x)}=\sin^{-1}(\cos\text{x})$

$\text{f(x)}=\sin^{-1}\Big[\sin\Big(\frac{\pi}{2}-\text{x}\Big)\Big]$

$\text{f(x)}=\frac{\pi}{2}-\text{x}$

Function is continuous at x = 0.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from CONTINUITY AND DIFFERENTIABILITY→CONTINUITY AND DIFFERENTIABILITY — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

In $( - 4,\,4)$ the function $f(x) = \int\limits_{ - 10}^x {({t^4} - 4){e^{ - 4t}}dt} $ has
→
If $y = {\tan ^{ - 1}}\sqrt {{{a - x} \over {a + x}}} $, then ${{dy} \over {dx}} = $
→
The area bounded by the curve $y^2=8 x,$ the $x-$ axis and the lastus rectum is :
→
Given that $\left[\begin{array}{ll}1 & x\end{array}\right]\left[\begin{array}{cc}4 & 0 \\ -2 & 0\end{array}\right]=0$, the value of $x$ is ;
→
Solution of the following $LP$ problem

Minimize $z=-3 x+2 y$

subject to $0 \leq x \leq 4,1 \leq y \leq 6, x+y \leq 5$ is $.....$

→
If $x + y = 8,$ then the maximum value of $xy$ is :
→
Consider the following system of equations : $x+2 y-3 z=a$ ; $2 x+6 y-11 z=b$ ; $x-2 y+7 z=c$    where $a , b$ and $c$ are real constants. Then the system of equations :
→
If the function $f(x) = 2x^2 + 3x + 5$ satisfies $LMVT$ at $x = 3$ on the closed interval $[1, a]$ then the value of $a$ is equal to
→
If $f : [1, \infty ) \rightarrow [2, \infty)$ is given by $\text{f(x)}=\text{x}+\frac{1}{\text{x}},$ then $f^{-1}$ equals to:
→
Let $R = \{ (3,\,3),\;(6,\;6),\;(9,\,9),\;(12,\,12),\;(6,\,12),\;(3,\,9),(3,\,12),\,(3,\,6)\} $ be a relation on the set $A = \{ 3,\,6,\,9,\,12\} $. The relation is
→