- A${C_n}{H_n}COOH$
- B${C_n}{H_{2n + 1}}COOH$
- C${C_n}{H_{2n}}{O_2}$
- ✓Both $(b)$ and $(c)$
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$(A)$ The acidity of compound $I$ is due to delocalization in the conjugate base.
$(B)$ The conjugate base of compound IV is aromatic.
$(C)$ Compound II becomes more acidic, when it has a $- NO _2$ substituent.
$(D)$ The acidity of compounds follows the order $I > IV > V > II > III$.

(Given, $\frac{ d (\ln K )}{ d \left(\frac{1}{T}\right)}=-\frac{\Delta H^{\ominus}}{ R }$, where the equilibrium constant, $K =\frac{ p _{ z }}{ p ^{\ominus}}$ and the gas constant, $R =8.314$ $\left.J K ^{-1} mol ^{-1}\right)$
($1$) The value of standard enthalpy, $\Delta H ^{\ominus}$ (in $kJ mol ^{-1}$ ) for the reaction is. . . . . . .
($2$) The value of $\Delta S^{\ominus}$ (in $J K ^{-1} mol ^{-1}$ ) for the given reaction, at $1000 K$ is. . . . . .
Give the answer or quetin ($1$) and ($2$)
