MCQ
The general solution of the equation $sin^{100}x\,-\,cos^{100} x= 1$ is
  • A
    $2n\pi  + \frac{\pi }{3},\,n \in I$
  • $n\pi  + \frac{\pi }{2},\,n \in I$
  • C
    $n\pi  + \frac{\pi }{4},\,n \in I$
  • D
    $2n\pi  - \frac{\pi }{3},\,n \in I$

Answer

Correct option: B.
$n\pi  + \frac{\pi }{2},\,n \in I$
b
We have $\sin ^{100} x-\cos ^{100} x=1$

or $\sin ^{100} x=1+\cos ^{100} x$

Since $L.H.S.\,\, \le 1\,\,and\,\,R.H.S. \ge 1,L.H.S. = R.HS. = 1$

Then, $x=n \pi+\frac{\pi}{2}, n \in I$

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