MCQ
The given reaction is
  • A
    Mendius reaction
  • B
    Stephen's reaction
  • Rosenmund's reduction
  • D
    Cannizzaro's reaction

Answer

Correct option: C.
Rosenmund's reduction
c

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Similar questions

The order of stability of the following tautomeric compounds is

$\mathop {\begin{array}{*{20}{c}}
  {OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\ 
  {C{H_2} = C - C{H_2} - C - C{H_3}} 
\end{array}}\limits_{(I)}  \rightleftharpoons $

$\mathop {\begin{array}{*{20}{c}}
  {OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\ 
  {C{H_3} - C - C{H_2} - C - C{H_3}} 
\end{array}}\limits_{(II)}  \rightleftharpoons $

$\mathop {\begin{array}{*{20}{c}}
  {OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\ 
  {C{H_3} - C = CH - C - C{H_3}} 
\end{array}}\limits_{(III)} $

Consider the following isomers of $[Cr(NH_3)_2 Cl_4]^-$ and answer the questions Out of these isomers
Choose the incorrect option
Which of the following reactions gives ${H_2}C = C = C = C{H_2}$
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The product $(P)$ of the following reaction
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$\underset{1}{\mathop{\begin{matrix}
   O\,\,\,\,\,\,\,\,\,\,\,\,  \\
   ||\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   C{{H}_{3}}COCHC{{H}_{3}}  \\
\end{matrix}}}\,$   $\underset{2}{\mathop{\begin{matrix}
   \,\,\,\,O \\
   \,\,\,\,|| \\
   C{{H}_{3}}CCl  \\
\end{matrix}}}\,$   $\underset{3}{\mathop{\begin{matrix}
   O\,\,\,\,\,\,\,\,\,  \\
   ||\,\,\,\,\,\,\,\,\,  \\
   C{{H}_{3}}CNHC{{H}_{3}}  \\
\end{matrix}}}\,$

Which of the following statements are correct about $\mathrm{Zn}, \mathrm{Cd}$ and $\mathrm{Hg}$ ?

$A$. They exhibit high enthalpy of atomization as the d-subshell is full.

$B$. $\mathrm{Zn}$ and $\mathrm{Cd}$ do not show variable oxidation state while $\mathrm{Hg}$ shows $+\mathrm{I}$ and + $II.$

$C$. Compounds of $\mathrm{Zn}, \mathrm{Cd}$ and $\mathrm{Hg}$ are paramagnetic in nature.

$D$. $\mathrm{Zn}, \mathrm{Cd}$ and $\mathrm{Hg}$ are called soft metals.

Choose the most appropriate from the options given below:

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If all products formed in the above reaction undergo reaction with $Br_2(CCl_4)$ individually then number of products formed will be :