MCQ
The graph of the linear equation y = 3x passes through the point.
- A$\Big(0,-\frac{2}{3}\Big)$
- B$\Big(-\frac{2}{3},0\Big)$
- C$\Big(0,\frac{2}{3}\Big)$
- D$\Big(\frac{2}{3},2\Big)$
✓
Answer
- $\Big(\frac{2}{3},2\Big)$
Solution:
$\text{y}=3\text{x}$
$\frac{\text{y}}{3}=\text{x}$
For, y = 2, the value of x will be $\frac{2}{3}$
So, $\Big(\frac{2}{3},2\Big)$
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