MCQ
The ${H^ + }$ ion concentration is $1.0 \times {10^{ - 6}}$ mole/litre in a solution. Its $pH $ value will be
- A$12$
- ✓$6$
- C$18$
- D$24$
$pH = - \,\log \,\,[1.00 \times {10^{ - 6}}]$; $pH = 6.$
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$[Co(NH_3)_6 ][Cr(NO_2)_6 ]$ and $[Cr(NH_3)_6][Co(NO_2)_6]$
$C{H_3}CHO\mathop {\xrightarrow{{(i)\,NaCN/HCl}}}\limits_{(ii)\,{H_2}O/{H^ \oplus }/\Delta } (A)\mathop {\xrightarrow{{Fenton}}}\limits_{reagent} (B)$
$(B)$ will be :