MCQ
The $\text{HCF}$ of $95$ and $152,$ is
- A$57$
- ✓$19$
- C$38$
- D$1$
✓
Answer
Correct option: B.
$19$
Using the factor tree for $95,$ we have:
Therefore,
$95=5 \times 19$
$152=2^3 \times 19$
$\operatorname{HCF}(95,152)=19$
Therefore,
$95=5 \times 19$
$152=2^3 \times 19$
$\operatorname{HCF}(95,152)=19$
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