MCQ
The highest oxidation state of $Cr$ will be
- A$2$
- B$3$
- C$4$
- ✓$6$
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| List-$I$ Species | List-$II$ Electronic distribution |
| $(A)$ $\mathrm{Cr}^{+2}$ | $(I)$ $3 \mathrm{~d}^8$ |
| $(B)$ $\mathrm{Mn}^{+}$ | $(II)$ $3 \mathrm{~d}^3 4 \mathrm{~s}^1$ |
| $(C)$ $\mathrm{Ni}^{+2}$ | $(III)$ $3\mathrm{~d}^4$ |
| $(D)$ $\mathrm{V}^{+}$ | $(IV)$ $3 \mathrm{~d}^5 4 \mathrm{~s}^1$ |
Choose the correct answer from the options given below:
$Pt|Cl_2| Cl^-(1\,M) ||Cl^-(1\,M)|Cl_2|Pt$
$P_1\, atm$ $P_2\, atm$
| $[A] (mol\,L^{-1})$ | $[B] (mol\,L^{-1})$ | Initial Rate $(mol\, L^{-1}\,s^{-1} )$ |
| $0.05$ | $0.05$ | $0.045$ |
| $0.10$ | $0.05$ | $0.090$ |
| $0.20$ | $0.10$ | $0.72$ |