MCQ
The hybrdization of $I{F_7}$ is
- ✓$s{p^3}{d^3}$
- B$s{p^2}d$
- C${d^2}s{p^3}$
- D$s{p^3}$
$I = [Xe]\;5{s^2},5{p^5}$ hence
$I{F_7}$ shows $s{p^3}{d^3}$ hybridization. So, its structure is pentagonal bipyramidal.
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$H_3PO_3 \to H_3PO_4 + PH_3$