Question
The hybridisation involved in $\ce{[Co(C_{2​}O_4​)_{3​}]^{3−}}$ is?

Answer

$\ce{[Co(C_2​O_4​)_3​]^{3−}= CO^{3+ }= [Ar]3d^{6 }}$
$\ce{C_2​O^{2−}​=}$ Strong field ligand.
$= \ce{d^2sp^3}$ Hybridisation.
$=$ Octahedral.
$\ce{(C_2​O_{4​})^{−2}}=$ Bidentate Ligand

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