MCQ
The hydrocarbon obtained by treating sodium ethanoate with soda lime is _________.
- AEthane
- BMethane
- CPropane
- DButane
Explanation:
CH3COONa + NaOH → CH4 + Na2CO3
CH3COONa = Sodium ethanoate
NaOH = Soda lime
CH4 = Methane
Na2CO3=Sodium carbonate
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$XeF _2, I _3^{+}, C _3 O _2, I _3^{-}, CO _2, SO _2, BeCl_2 \text { and } BCl _2^{\Theta}$