- AThermal stability : $HF > HCl > HBr$
- BLewis basic character: $PF_3 < PCl_3 < PBr_3$
- ✓$\%\, p-$ character : $NO_2^+ > NO_3^- > NH_4^+$
- DBond angle : $NH_3 > PH_3 > AsH_3$
Thermal stability: $HF\, >\, HCl\, > \,HBr \,> \,HI$
The decrease in thermal stability is due to decrease in bond dissociation enthalpy.
$\Delta_{\text {diss }} H :- HF \,>\, HCl\, > \,HBr \,>\, HI$
Bond angle: $NH _3\,>\, PH _3\,>\, AsH _3$
Lewis basic character: $PF _3\,<\, PCl _3\,<\, PBr _3$
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| List I (Complex) | List $II$ (Type of isomerism) |
| $A$. $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5\left(\mathrm{NO}_2\right)\right] \mathrm{Cl}_2$ | $I$. Solvate isomerism |
| $B$. $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5\left(\mathrm{SO}_4\right)\right] \mathrm{Br}$ | $II$. Linkage isomerism |
| $C$. $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]\left[\mathrm{Cr}(\mathrm{CN})_6\right]$ | $III$. Ionization isomerism |
| $D$. $\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{Cl}_3$ | $IV$. Coordination isomerism |
Choose the correct answer from the options given below:
$\mathop {C{H_2} = CH - Br}\limits_{(I)} $ $\mathop {{\text{C}}{{\text{H}}_3} - Br}\limits_{\left( {II} \right)} $ $\mathop {\begin{array}{*{20}{c}}
{C{H_3} - CH - Br} \\
{|\,\,} \\
{\,\,\,C{H_3}}
\end{array}}\limits_{\left( {III} \right)} $ $\mathop {C{H_3}C{H_2}Br}\limits_{\left( {IV} \right)} $

Compound $\to$ Oxidation state