Glucose exist is open chain as well as cyclic forms in its aqueous solution.
Glucose having $6 \mathrm{C}$ atoms so it is hexose and having aldehyde functional group so it is aldose.
Thus, aldohexose.
Glucose is monomer unit in sucrose with fructose.
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$\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,O}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,||}\\
{CH \equiv C - C - OH}
\end{array}}\limits_{\rm{I}} $ $\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||}\\
{C{H_2} = CH - C - OH}
\end{array}}\limits_{{\rm{II}}} $ $\mathop {\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O}\\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||}\\
{C{H_3} - C{H_2} - C - OH}
\end{array}}\limits_{{\rm{III}}} $$\mathop {\begin{array}{*{20}{c}}
\,\,\,{C{H_3}\,\,\,\,\,\,O}\\
\,\,\,{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||}\\
{C{H_3} - CH - C - OH}
\end{array}}\limits_{{\rm{IV}}} $
