- ✓$C_ {60}$ is an allotropic form of carbon
- B$O_3$ is an allotropic form of oxygen
- C$S_8$ is the only allotropic form of sulphur
- DRed phosphorus is more stable in air than white phosphorus
No. of $\pi-$ bonds $=4$
(b)
No. of $\pi-$ bonds $=4$
Total $\pi-$ bonds $=8$
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(At. no. : $Sc = 21, Ti = 22, Ni = 28,$$ Cu = 29, Co = 27$)
$I.$ $Zn +$ conc. $HNO_3$ (hot) $\rightarrow Zn(NO_3)_2 + X + H_2O$
$II.$ $Zn +$ dil. $HNO_3$ (cold) $\rightarrow Zn(NO_3)_2 + Y + H_2O$
Compounds $X$ and $Y$ are respectively
| List I (Complex) | List $II$ (Type of isomerism) |
| $A$. $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5\left(\mathrm{NO}_2\right)\right] \mathrm{Cl}_2$ | $I$. Solvate isomerism |
| $B$. $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_5\left(\mathrm{SO}_4\right)\right] \mathrm{Br}$ | $II$. Linkage isomerism |
| $C$. $\left[\mathrm{Co}\left(\mathrm{NH}_3\right)_6\right]\left[\mathrm{Cr}(\mathrm{CN})_6\right]$ | $III$. Ionization isomerism |
| $D$. $\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{Cl}_3$ | $IV$. Coordination isomerism |
Choose the correct answer from the options given below:
The Gibbs free energy change for the above reaction at $298\, K$ is $x \times 10^{-1} \,k\,J\, mol ^{-1}$;
The value of $x$ is ..... [nearest integer]$\left [\text { Given : } E _{ Cu ^{2} / / Cu }=0.34\, V ; E _{ Sn ^{2} / Sn }^{\ominus}=-0.14 \,V ; F=96500\, C\, mol ^{-1}\right]$
