MCQ
The incorrect statement regarding molecular orbital $(s)$ is
  • A
    If there is a nodal plane perpendicular to the internuclear axis and lying between  the nuclei of bonded atoms then corresponding orbitals is antibonding $M.O.$
  • B
    If a nodal plane lies in the inter-nuclear axis, then corresponding orbitals is $pi(\pi)$  bonding $M .O.$
  • C
    The $\sigma$ -bonding molecular orbital does not contain nodal planes containing  the ternuclear axis
  • The $\delta$ -bonding molecular orbital possesses three nodal planes containing  the internuclear axis.

Answer

Correct option: D.
The $\delta$ -bonding molecular orbital possesses three nodal planes containing  the internuclear axis.
d
The $\delta$ molecular orbital possesses $2$ nodal planes containing the internuclear axis.

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[Atomic number: $S =16, C 1=17, I =53$ and $Xe =54$ ]

$LIST-I$ contains metal species and $LIST-II$ contains their properties.

$LIST-I$ $LIST-II$
$(I)$ $\left[ Cr ( CN )_6\right]^{4-}$ $(P)$ $t_{2 g }$ orbitals contain 4 electrons
$(II)$ $\left[ RuCl _6\right]^{2-}$ $(Q)$ $\mu$ (spin-only) $=4.9 BM$
$(III)$ $\left[ Cr \left( H _2 O \right)_6\right]^{2+}$ $(R)$ low spin complex ion
$(IV)$ $\left[ Fe \left( H _2 O \right)_6\right]^{2+}$ $(S)$ metal ion in $4$+ oxidation state
  $(T)$ $d^4$ species

[Given : Atomic number of $Cr =24, Ru =44, Fe =26$ ] Metal each metal species in $LIST-I$ with their properties in $LIST-II$, and choose the correct option