$NH_3$ can react with $B_2H_6,$
${B_2}{H_6} + 2N{H_3}\xrightarrow{{warm}}{[B{H_2}.2N{H_3}]^ + }.{[B{H_4}]^ - }$ $\xrightarrow{{200{\,^o}C}}{B_3}{N_3}{H_6}$ (Inorganic benzene)
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$\begin{array}{*{20}{c}}
{C{H_3}CH = C{H_2} + {H_2}O\overset {{H^ + }} \longleftrightarrow C{H_3} - CH - C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,OH}
\end{array}$
The reaction takes place in accordance with
Mark the correct option
Coordination no. $-$ Oxidation on. $-$ No. of $d-$electrons $-$ Unpaired $d-$electrons
