The inequality representing the following graph is: - Vidyadip

MCQ

The inequality representing the following graph is:

A
$\text{|x|}<3$
B
$\text{|x|}\leq3$
C
$\text{|x|}>3$
D
$\text{|x|}\geq3$

✓

Answer

$\text{|x|}\leq3$

Solution:

As according to the graph,

x lies between −3 and 3

$\Rightarrow-3\leq\text{x}\leq3$

$\Rightarrow|\text{x}|\leq3$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Linear Inequalities→Linear Inequalities — all question types→MATHS STD 11 Science question papers→Rajasthan Board STD 11 Science question papers→Rajasthan Board question paper generator→

Similar questions

The image of the point P(1, 3, 4) in the plane 2x - y + z = 0 is:

The domain of the function $\text{f}(\text{x})= ^{7-\text{x}}\text{P}_\text{x-3}$ is:

$\frac{d}{d x}\left(\log _a x\right)$ is equal to :

If $|\text{x}+2|\leq9,$ then:

$\text{x}\in(-7,11)$
$\text{x}\in[-11, 7]$
$\text{x}\in[-\infty,-7)\cup(11,\infty) $
$\text{x}\in(-\infty,-7)\cup[11,\infty) $

Equation of the diameter of the circle x² + y² − 2x + 4y = 0 which passes through the origin is:

x + 2y = 0
x − 2y = 0
2x + y = 0
2x − y = 0

Let A = {1, 2, 3, 4, 5} and R be a relation from A to A, R = {(x, y) : y = x + 1}. Find the range:

The number of ways in which a team of eleven players can be selected from 22 players always including 2 of them and excluding 4 of them is.

¹⁶C₁₁
¹⁶C₅
¹⁶C₉
²⁰C₉

If $\omega $ is a complex cube root of unity, then $(x-y)(x\omega -y)$ $(x{{\omega }^{2}}-y)=$

if P(0, 1, 2), Q (4, -2, 1) and O(0, 0, 0) are three points, then $\angle\text{POQ}=$

Two vertices of a triangle are (-2, -1) and (3, 2) and third vertex lies on the line x + y = 5. If the area of the triangle is 4 square units, then the third vertex is: