MCQ
The isomeric alcohol which has a chiral carbon atom is
- A$n$ -butyl alcohol
- B$iso$ -butyl alcohol
- ✓$sec$-butyl alcohol
- D$tert$ -butyl alcohol

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| $I.E.\, (kJ \,mol^{-1})$ | $I.E.\, (kJ\, mol^{-1})$ |
| $A_{(g)} \to A^+_{(g)}+e^-,$ $A_1$ | $B_{(g)} \to B^{+}_{(g)}+e^-,$ $B_1$ |
| $B^+_{(g)} \to B^{2+}_{(g)}+e^-,$ $B_2$ | $C_{(g)} \to C^{+}_{(g)}+e^-,$ $C_1$ |
| $C^+_{(g)} \to C^{2+}_{(g)}+e^-,$ $C_2$ | $C^{2+}_{(g)} \to C^{3+}_{(g)}+e^-,$ $C_3$ |
If monovalent positive ion of $A,$ divalent positive ion of $B$ and trivalent positive ion of $C$ have zero electron. Then incorrect order of corresponding $I.E.$ is
${N_2} + {O_2}$ $\rightleftharpoons$ $2NO - 43,200\,kcal$
$I.\,\,NaBH_4 + BF_3$ (in ether) $\to $
$II.\,\, NaBH_4 + I_2 \to $
$III.\,\, BF_3 + NaH \to $