MCQ
The $ IUPAC$ name of $C{H_3}C \equiv CCH{(C{H_3})_2}$ is
  • $4-$ methyl $-2-$ pentyne
  • B
    $4, 4-$ dimethyl $-2-$ butyne
  • C
    Methyl isopropyl acetylene
  • D
    $2-$ methyl $-4-$ pentyne

Answer

Correct option: A.
$4-$ methyl $-2-$ pentyne
a
$\begin{matrix} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}  \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|  \\ {{H}_{3}}C-C\equiv C-CH  \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|  \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{H}_{3}}  \\ \end{matrix}$ is the required structure.

Now, we start numbering from the leftmost carbon as by doing that, the triple bond will be on $2^{nd}$ carbon.

Hence, the name of the compound will be $4$ methyl-$2$-pentyne as there are $5$ carbons on the parent chain.

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