MCQ
The $ IUPAC$ name of $C{H_3}C \equiv CCH\,{(C{H_3})_2}$ is
- ✓$4$ methyl$-2 $ pentyne
- B$4, 4-$dimethyl$-2-$butyne
- CMethyl isopropyl acetylene
- D$2-$methyl$-4-$pentyne
Now, we start numbering from the leftmost carbon as by doing that, the triple bond will be on $2^{nd}$ carbon.
Hence, the name of the compound will be $4$methyl-$2$-pentyne as there are $5$ carbons on the parent chain.
Hence, (a) is correct answer.
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