MCQ
The $ IUPAC$ name of $C{H_3}C \equiv CCH{(C{H_3})_2}$ is
- ✓$4-$ methyl $-2-$ pentyne
- B$4, 4-$ dimethyl $-2-$ butyne
- CMethyl isopropyl acetylene
- D$2-$ methyl $-4-$ pentyne
Now, we start numbering from the leftmost carbon as by doing that, the triple bond will be on $2^{nd}$ carbon.
Hence, the name of the compound will be $4$ methyl-$2$-pentyne as there are $5$ carbons on the parent chain.
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| $(n)$-$(l)$-$(m)$-$(s)$ | |
| $(i)$ | $(3)$-$(2)$-$(1)$- $(+1/2)$ |
| $(ii)$ | $(2)$-$(2)$-$(1)$- $(+1/2)$ |
| $(iii)$ | $(4)$-$(3)$-$(-2)$- $(-1/2)$ |
| $(iv)$ | $(1)$-$(0)$-$(-1)$- $(-1/2)$ |
| $(v)$ | $(3)$-$(2$-$(3)$- $(+1/2)$ |
Which of the following sets of quantum number is not possible ?
$(i)$ Chlorobenzene
$(ii)$ Benzene
$(iii)$ Anilinium chloride
$(iv)$ Toluene
Product $(A)$ of the above reaction is