- AChlorotris (triphenylphosphine) rhodium $(I)$
- ✓Chlorotris (triphenylphosphine) rhodium $(IV)$
- CChlorotris (triphenylphosphine) rhodium $(O)$
- DChlorotris (triphenylphosphine) rhodium $(VI)$
$\therefore \quad \mathrm{x}-5+1=-2$
$\therefore \quad \mathrm{x}-4=-2$
$\therefore \quad x=+2$
$\therefore$ oxidation state of $\mathrm{Fe}$ is +2
$\mathrm{Na}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{5} \mathrm{NOS}\right] \Rightarrow \mathrm{Na}^{+}\left[\mathrm{Fe}(\mathrm{CN})_{5} \mathrm{NOS}\right]^{4-}$
$\therefore \quad \mathrm{x}-5+1=-2$
$\therefore \quad x=+2$
The $0 .$ S of $F$ e in both the molecules in +2 .
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$4N{H_3}(g)\,+\,5{O_2}(g)\,\, \rightleftharpoons \,4NO(g)\, + \,6{H_2}O(g)\, + \,Heat$
$(i)\,\begin{array}{*{20}{c}}
{C{H_3} - \mathop C\limits^ \oplus - C{H_3}} \\
| \\
{\,\,\,\,\,\,OC{H_3}}
\end{array}$
$(ii)\,\begin{array}{*{20}{c}}
{C{H_3} - \mathop C\limits^ \oplus - C{H_3}} \\
| \\
{\,\,\,\,\,\,C{H_3}}
\end{array}$
$(iii)\begin{array}{*{20}{c}}
{C{H_3} - \mathop C\limits^ \oplus {H_2} - NH} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
$(iv)\,C{H_3} - \mathop C\limits^ \oplus {H_2}$