MCQ
The labelled carbon goes with
- A$Ph-\overset{14}{\mathop{C{{O}_{2}}}}H$
- ✓$\overset{14}{\mathop{C{{O}_{2}}}}\,$
- C$Ph-\overset{14}{\mathop{C{{H}_{2}}}}\,-C{{O}_{2}}H$
- D$\overset{14}{\mathop{C{{H}_{4}}}}\,$
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$\Delta H_f^o[CO_2,g] = -394 \,kJ/mol$
$\Delta H_f^o[H_2O,l] = -286\, kJ/mol$
$\Delta H_f^o [propene ,g] = 20\,kJ/mol$
cyclopropane $(g)$ $\to$ propene $(g)$ ; $\Delta H^o_{isomerisation} = $ $-33\,kJ/mol$.
Calculate $\Delta H^o_{combustion}$ [cyclopropane, $(g)$]
......$ kJ/mol$
Reason : In the complex, the coordination number of $Fe$ is $6$.