MCQ
The labelled $-O^{18}$ will be in


- A$H_2O$
- ✓Methyl benzoate
- CBoth $(a)$ and $(b)$
- DBenzoic acid

Product of the reaction is methyl benzoate $\begin{array}{*{20}{c}}
{O\,\,\,\,\,\,\,\,\,\,\,\,} \\
{||\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{Ph - C - \mathop O\limits^{18} - C{H_3}}
\end{array}$
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