MCQ
The labelled $-O^{18}$ will be in
  • A
    $H_2O$
  • Methyl benzoate
  • C
    Both $(a)$ and $(b)$
  • D
    Benzoic acid

Answer

Correct option: B.
Methyl benzoate
b
$(b)$ In esterification acid gives $OH^{\ominus}$ whereas alcohol gives $H^+$.

Product of the reaction is methyl benzoate $\begin{array}{*{20}{c}}
  {O\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {||\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {Ph - C - \mathop O\limits^{18}  - C{H_3}} 
\end{array}$

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