
- A$H_2O$
- ✓Methyl benzoate
- CBoth $(a)$ and $(b)$
- DBenzoic acid

Product of the reaction is methyl benzoate $\begin{array}{*{20}{c}}
{O\,\,\,\,\,\,\,\,\,\,\,\,} \\
{||\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{Ph - C - \mathop O\limits^{18} - C{H_3}}
\end{array}$
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$(i)\, EMF$ of cell = (Oxidation potential of anode) $-$ (Reduction potential of cathode)
$(ii)\,EMF$ of cell = (Oxidation potential of anode) $+$ (Reduction potential of cathode)
$(iii)\,EMF$ of cell = (Reductional potential of anode) $+$ (Reduction potential of cathode)
$(iv)\,EMF$ of cell = (Oxidation potential of anode) $-$ (Oxidation potential of cathode)
Which of the above relations are correct?
Product is

$HC \equiv CH\mathop {\xrightarrow{{{\text{1% HgS}}{{\text{O}}_{\text{4}}}}}}\limits_{20\% {H_2}S{O_4}} A\xrightarrow{{C{H_3}MgX}}B\xrightarrow{{[O]}}$