MCQ
The Lanthanoid contraction refers to decrease in the:
- AValence electrons of the Lanthanide series.
- ✓Ionic radius of the series.
- CThe density of the series.
- DNuclear mass of the series.
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Product obtained in the above reaction is
${C{H_3} - C{H_2} - CH = C{H_2} + HBr\,\to \,CH _{3}- CH _{2}- CH _{2}- C^{+}H _{2}+ Br ^{-}} _{"A"}$
${C{H_3} - C{H_2} - CH = C{H_2} + HBr\, \to \,CH _{3}- CH _{2}- C^{+}H - CH _{3}+ Br ^{-}}_{"B"}$

Product $ X$ is
$\begin{array}{|l|l|} \hline Column\,\,I & Column\,\,II \\ \hline (A)\,XeF_6 & (i)\,\,distortedoctahedral \\ \hline (B)\,XeO_3 & (ii)\,\,square\,\,planar \\ \hline (C)\,XeOF_4 & (iii)\,\,pyramidal \\ \hline (D)\,XeF_4 & (iv)\,\,square\,\,pyramidal \\ \hline \end{array}$
End product $(X)$ of the above reaction is