MCQ
The larger of two complementary angles exceeds the smaller by 16 degrees. Find them.
  • A
    $58^{\circ}, 32^{\circ}$
  • $53^{\circ}, 37^{\circ}$
  • C
    $64^{\circ}, 26^{\circ}$
  • D
    $29^{\circ}, 63^{\circ}$

Answer

Correct option: B.
$53^{\circ}, 37^{\circ}$
(b): Let the two angles be $x$ and $y$, where $x>y$.
According to the question,
$x+y=90^{\circ}\ldots(i)$
and $x-y=16^{\circ}$$\ldots(ii)$
Adding (i) and (ii), we get $2 x=106^{\circ} \Rightarrow x=53^{\circ}$
Substituting the value of $x$ in (i), we get
$y=90^{\circ}-53^{\circ}=37^{\circ}$

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