decomposed to $\mathrm{H}_{2} \mathrm{S}$ and $\mathrm{HCN}$ by $HNO_{3}$
$\mathrm{NaCN}+\mathrm{HNO}_{3} \rightarrow \mathrm{NaNO}_{3}+\mathrm{HCN}$
$\mathrm{Na}_{2} \mathrm{S}+2 \mathrm{HNO}_{3} \rightarrow 2 \mathrm{NaNO}_{3}+\mathrm{H}_{2} \mathrm{S}$
These will escape from the solution and will not interfere with the test for halogens.
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$I = -3.04\,V$,
$II = -1.90\,V$,
$III = 0\,V$,
$IV = 1.90\,V$
Statement $I :$ Pure Aniline and other arylamines are usually colourless.
Statement $II :$ Arylamines get coloured on storage due to atmospheric reduction.
In the light of the above statements, choose the most appropriate answer from the options given below:
$\left[\right.$ Given : $K _{ sp }( AgBr )=4.9 \times 10^{-13}$ at $298 K$
$\lambda_{ Ag ^{+}}^0=6 \times 10^{-3} Sm ^2\,mol ^{-1}$
$\lambda_{ Br ^{-}}^0=8 \times 10^{-3} Sm ^2\,mol ^{-1}$
$\left.\lambda_{ NO _3^{-}}^0=7 \times 10^{-3} Sm ^2\,mol ^{-1}\right]$