Question
The last two digits of $2015! + 3^{2015}$ is-

Answer

d
$2015! + {3^{2015}}$

$2015!$ has last two digits zero.

$3^{2015} \equiv 3 \cdot\left(3^{2014}\right)$

$\equiv 3.9^{1007}=(3)(10-1)^{1007}$

on expansion last two digits $\equiv 07$

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