MCQ
The length of the longest interval, in which the function $3\sin x - 4{\sin ^3}x $ is increasing, is
  • ${\pi \over 3}$
  • B
    ${\pi \over 2}$
  • C
    ${{3\pi } \over 2}$
  • D
    $\pi $

Answer

Correct option: A.
${\pi \over 3}$
a
(a) $3\sin x - 4{\sin ^3}x = \sin 3x$

It is increasing, when $ - \pi /2 \le 3x \le \pi /2$

$i.e.,$ $ - \pi /6 \le x \le \pi /6$.

$\therefore$ The length of interval $= \left| {\,\frac{\pi }{6} - \left( { - \frac{\pi }{6}} \right)\,} \right|\, = \,\frac{\pi }{3}$.

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